
Recent Posts
 A^2 = B^3 + C^3
 Set {4,b,c,d,e} such that the product of any two of them increased by 1 is a square
 smallest integer whose first n multiples all contain a 3
 Set {3,b,c,d,e} such that the product of any two of them increased by 1 is a square
 Set {2,b,c,d,e} such that the product of any two of them increased by 1 is a square
Recent Comments
Archives
 February 2017
 January 2017
 December 2016
 November 2016
 October 2016
 September 2016
 August 2016
 July 2016
 June 2016
 May 2016
 April 2016
 March 2016
 February 2016
 January 2016
 December 2015
 November 2015
 October 2015
 September 2015
 August 2015
 July 2015
 June 2015
 May 2015
 April 2015
 March 2015
 February 2015
 January 2015
 December 2014
 November 2014
 October 2014
 September 2014
 August 2014
 July 2014
 June 2014
 May 2014
 April 2014
 March 2014
 February 2014
 January 2014
 December 2013
 November 2013
 October 2013
 September 2013
 August 2013
 July 2013
 June 2013
 May 2013
 April 2013
 March 2013
 February 2013
 January 2013
 December 2012
 November 2012
 October 2012
 September 2012
 August 2012
 July 2012
 June 2012
 May 2012
 April 2012
 March 2012
 February 2012
 January 2012
Categories
Meta
Tag Archives: 3digit Numbers
3digit num3ers whose odd powers (1 to 19) end with the same num3er
This is the list of all 3 digit numbers, powers 1 to 19
4digit number abcd = (k+a)(k+b)(k+c)(k+d)
abcd = (k + a)(k + b)(k + c)(k + d) abcd is a 4digit number and k is a positive integer. For example, k = 5 1500 = (5 + 1)(5 + 5)(5 + 0)(5 + … Continue reading
Posted in Math Beauty, Number Puzzles
Tagged 3digit Numbers, 4digit Num3ers, digital product, DigitProduct, Factors
2 Comments
3digit Num3ers of the form x(xy)+y(yz)+z(zx)=k, k=0,1,..,9
To find all 3digit numbers xyz such that x(x – y) + y(y – z) + z(z – x) = k k = 0 Solutions: 0, 111, … Continue reading
Posted in Math Beauty, Number Puzzles
Tagged 3digit Numbers, x(xy)+y(yz)+z(zx)=k
Leave a comment
3digit Num3ers w/ consecutive digits
123 + 132 + 213 + 231 + 312 + 321 = 1332 (123 + 132 + 213 + 231 + 312 + 321)/2 = 666 (123 + 132 + 213 + 231 + 312 + 321)/3 = 444 (123 … Continue reading
Deleting the middle digit of 3digit/5digit numbers
(1) Let N be a 3digit number (whose first digit is nonzero) and let M be the 2digit number formed from N by deleting its middle digit N = abc … Continue reading
Posted in Number Puzzles
Tagged 3digit Numbers, 5digit number, Delete middle digit
Leave a comment
Consecutive integers divisible by 3,5,7,9
Let’s look for consecutive numbers that are divisible by 3, 5, 7, 9 in that order (1) 3digit numbers: 159 = 3 * 53 … Continue reading
Num3ers formed by its digits
132 = 13 + 31 + 12 + 32 + 21 + 23 123 = 132 – (1 + 2^3) 312 = … Continue reading
3digit numbers ABC = k*(A + B + C)
To find all 3digit numbers abc such that 100*a + 10*b + c = k*(a + b + c) = k*a + k*b + k*c For example, k = 11 198 … Continue reading
Products of 3digit Num3ers are pandigital
For example, The 3digit number 107 is multiplied by three different digits 3, 7, 8 107 * 3 = 321 107 * 7 = 749 107 * 8 = 856 The 3 products … Continue reading
Concatenation puzzle: when (A  B) / B is an integer
Concatenation is the joining of two numbers by their numerals. That is, the concatenation of 444 and 777 is 444777. Concatenation of numbers A and B is denoted A  … Continue reading