Diophantine equations : 2^A – 3^B = 3^D – 2^C

 
 
Find all the solutions to the Diophantine equations

2^{A} \; - \; 3^{B} \; = \; 3^{D} \; - \; 2^{C}
2^{A} \; - \; 3^{B} \; = \; 2^{C} \; + \; 3^{D}
3^{B} \; - \; 2^{A} \; = \; 2^{C} \; + \; 3^{D}

 

 
 

 
 

 
 

 
 
 
 
 

 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 

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About benvitalis

math grad - Interest: Number theory
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