Make {(x^2 + x*y + y^2), (x^2 – x*z + z^2), (y^2 + y*z + z^2)} squares … Part 5

$x^2 \; + \; x \, y \; + \; y^2 \; = \; A^2$
$x^2 \; - \; x \, z \; + \; z^2 \; = \; B^2$
$y^2 \; + \; y \, z \; + \; z^2 \; = \; C^2$

These are the first few solutions I found: