## Pythagorean triangle (a, b, c): {a^2 – a, b^2 – b, c^2 – c} to be made squares

Find a Pythagorean triangle   $(a, \; b, \; c)$   such that the square of any side exceeds that side by a square

$a^2 \; - \; a \; = \; m^2$
$b^2 \; - \; b \; = \; n^2$
$c^2 \; - \; c \; = \; p^2$