## Num3er 13

$13 \; = \; 2^2 \; + \; 3^2$
$13^4 \; = \; 119^2 \; + \; 120^2$

13 as well as its biquadrate is the sum of the squares of two consecutive integers.

Is it possible to find another integer sharing this property?

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## About benvitalis

math grad - Interest: Number theory
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