(c – a – b)^3 – 27*a*b*c = 1

 

Find integers   a, b, c   such that
 

(c - a - b)^3 \; - \; 27 \, a b c \; = \; 1

 

 

Pipo found solution for negative integers:

c = -313,     a = -84,     b = -14

 
 

The challenge is to find a solution with   c, a, b   being positive integers.

 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 

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About benvitalis

math grad - Interest: Number theory
This entry was posted in Number Puzzles and tagged . Bookmark the permalink.

2 Responses to (c – a – b)^3 – 27*a*b*c = 1

  1. pipo says:

    Found one with negative integers.
    (-313- -84- -14)^3 – 27(-313 * -84 * -14) =1

    pipo

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