Part 2 – N^4 = 2(A^4) + B^4 + 2(C^4)

 
 
Previous blog:   A^4 + B^4 + C^4 + D^4 + E^4 = N^4

 
 

for   N \; \leq \; 100
 

   5^4 \; = \; 2(2^4) \; + \; 3^4 \; + \; 2(4^4)

  10^4 \; = \; 2(4^4) \; + \; 6^4 \; + \; 2(8^4)
  15^4 \; = \; 2(6^4) \; + \; 9^4 \; + \; 2(12^4)
  20^4 \; = \; 2(8^4) \; + \; 12^4 \; + \; 2(16^4)
  25^4 \; = \; 2(10^4) \; + \; 15^4 \; + \; 2(20^4)
  30^4 \; = \; 2(12^4) \; + \; 18^4 \; + \; 2(24^4)
  35^4 \; = \; 2(14^4) \; + \; 21^4 \; + \; 2(28^4)
  40^4 \; = \; 2(16^4) \; + \; 24^4 \; + \; 2(32^4)
  45^4 \; = \; 2(18^4) \; + \; 27^4 \; + \; 2(36^4)
  50^4 \; = \; 2(20^4) \; + \; 30^4 \; + \; 2(40^4)
  55^4 \; = \; 2(22^4) \; + \; 33^4 \; + \; 2(44^4)
  60^4 \; = \; 2(24^4) \; + \; 36^4 \; + \; 2(48^4)
  65^4 \; = \; 2(26^4) \; + \; 39^4 \; + \; 2(52^4)
  65^4 \; = \; 2(4^4) \; + \; 63^4 \; + \; 2(32^4)
  70^4 \; = \; 2(28^4) \; + \; 42^4 \; + \; 2(56^4)
  75^4 \; = \; 2(30^4) \; + \; 45^4 \; + \; 2(60^4)
  80^4 \; = \; 2(32^4) \; + \; 48^4 \; + \; 2(64^4)
  85^4 \; = \; 2(12^4) \; + \; 77^4 \; + \; 2(54^4)
  85^4 \; = \; 2(34^4) \; + \; 51^4 \; + \; 2(68^4)
  90^4 \; = \; 2(36^4) \; + \; 54^4 \; + \; 2(72^4)
  95^4 \; = \; 2(38^4) \; + \; 57^4 \; + \; 2(76^4)

100^4 \; = \; 2(40^4) \; + \; 60^4 \; + \; 2(80^4)

 
Contributor:   Paul

 
 
 
 
 
 
 
 
 
 
 
 
 
 
 

Advertisements

About benvitalis

math grad - Interest: Number theory
This entry was posted in Number Puzzles and tagged . Bookmark the permalink.

Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out / Change )

Twitter picture

You are commenting using your Twitter account. Log Out / Change )

Facebook photo

You are commenting using your Facebook account. Log Out / Change )

Google+ photo

You are commenting using your Google+ account. Log Out / Change )

Connecting to %s