## Pandigital | 7*p, 8*q, 9*r; p,q,r are prime numbers

$413 \; = \; 7 \; \times \; 59$ ………. $= \; 7 \, p_1$
$568 \; = \; 8 \; \times \; 71$ ………. $= \; 8 \, p_2$
$927 \; = \; 9 \; \times \; 103$ ……… $= \; 9 \, p_3$

The combined digits of the numbers   $7 \, p_1, \; 8 \, p_2, \; 9 \, p_3$   use all nine digits 1 – 9 exactly once each

$413 \; || \; 568 \; || \; 927 \; = \; 413568927$

and the product of   $7 \, p_1, \; 8 \, p_2, \; 9 \, p_3$

$413 \; \times \; 568 \; \times \; 927 \; = \; 217459368$

is a 9-digit number containing each digit 1 – 9.