Identity of two equal sums of n distinct squares

 
 

Establish the following identity:

 

\sum_{k=0}^{n-2} (2^k - 1)^2 \; + \; (3(2^{n-1}) - 1)^2 \; = \; \sum_{k=2}^{n} (2^k + 1)^2 \; + \; (2^n - 4)^2

 

 
 
 
 
 

 
 
 
 
 
 
 
 
 
 
 
 
 
 

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About benvitalis

math grad - Interest: Number theory
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