132, 264, 396 ;

132 = (13+31) + (32+23) + (21+12)

264 = (26+62) + (64+46) + (42+24)

396 = (39+93) + (96+69) + (63+36)

Now, find a 5-digit number, with distinct nonzero digits, which is equal to the sum of all the different 3-digit integers formed by the three digit permutations of its five digits.

35964. with the 3 digit permutations

{359,356,354,395,396,394,365,369,364,345,349,346}

{539,536,534,593,596,594,563,569,564,543,549,546}

{935,936,934,953,956,954,963,965,964,943,945,946}

{635,639,634,653,659,654,693,695,694,643,645,649}

{435,439,436,453,459,456,493,495,496,463,465,469}

Solved by Paul.

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That would be

35964. with the 3 digit permutations.{359,356,354,395,396,394,365,369,364,345,349,346,539,536,534,593,596,594,563,569,564,543,549,546,935,936,934,953,956,954,963,965,964,943,945,946,635,639,634,653,659,654,693,695,694,643,645,649,435,439,436,453,459,456,493,495,496,463,465,469}.

Paul.

Nice.