Diophantine equation: (x^8 + y^8 + z^8) = 2(x^16 + y^16 + z^16)

 
 

Find integer solutions to

(x^8 + y^8 + z^8) \; = \; 2 \,(x^{16} + y^{16} + z^{16})

 
 
 
 

 
 
 
 
 
 
 
 
 
 
 
 
 
 

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About benvitalis

math grad - Interest: Number theory
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