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 A^2 = B^3 + C^3
 Set {4,b,c,d,e} such that the product of any two of them increased by 1 is a square
 smallest integer whose first n multiples all contain a 3
 Set {3,b,c,d,e} such that the product of any two of them increased by 1 is a square
 Set {2,b,c,d,e} such that the product of any two of them increased by 1 is a square
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Monthly Archives: October 2015
Word Play: A=1, B=2, C=3, D=4, E=5, ..
A = 1 B = 2 C = 3 D = 4 E = 5 F = … Continue reading
Palindromes P divisible by 19 & DigitSum(P) = 2,3,…,100
Find other palindromes divisible by 19. Paul found: 4 : 11000000011 = 7*11*11*13*19*52579 6 : 1200021 = 3*19*37*569 7 : 200111002 = … Continue reading
PPT & x^2 – 2*y^2 = 7
Using the parametrization of primitive Pythagorean triples as where the sum p of its two legs can be expressed as the Pelllike equation, Eq #1 When p is a prime If Eq #1 … Continue reading
Palindromes P divisible by 17 & DigitSum(P) = 2,3,…,100
Find more palindromes divisible by 17 David & Paul found: 35 : 35 : 35 : 35 : 35 : 35 : 35 : 35 : 35 : … Continue reading
PPT (a,b,c)  2(b*c)^2 = b^4 + c^4 – a^4
The integers form a Pythagorean triple. And, that is, All the Primitive Pythagorean Triples (PPT) with : ………… ………. ………. ………. ……… ……… … Continue reading
ndigit integers which are also an nth power
Here are some examples: 1digit: 2digit: 3digit: 4digit: 5digit: 6digit: 7digit: 8digit: 9digit: 10digit: 11digit: 12digit: 13digit: 14digit: 15digit: … Continue reading
Palindromes P divisible by 13 & DigitSum(P) = 2,3,…,100
Can you find palindromes divisible by 13 and whose sum of digits is: 32, 38, 39, …, 100? Pipo and Paul found: 32: 88088 = 2*2*2*7*11*11*13 38: 1974791 = … Continue reading
Palindromes P divisible by 7 & DigitSum(P) = 2,3,…,40
Can you find palindromes divisible by 7 and whose sum of digits is: 5, 27, 29, 31, 33, 35, 37, 38, 39, 40? Pipo found : 4 : 1002001 5 : 1011101 6 : … Continue reading
Equation : x^2 ± k*y^2 are square numbers, x a prime number less than 1000
Here are the prime numbers, less than 1000, that are solutions to the two equations :
Cubes with same digits
The digits of can be permuted to form cube whose digits can be permuted to produce two other cubes : and three other cubes : Paul found: … Continue reading