Equation : x^2 ± 80*y^2 are square numbers

 

x^2 \; + \; 80 \, y^2 \; = \; a^2
x^2 \; - \; 80 \, y^2 \; = \; b^2

 

First few primitive solutions :

x = 41
y = 3
a = 49
b = 31
 

x = 3344161
y = 373674
a = 4728001
b = 113279
 

x = 249850594047271558364480641
y = 1338557465705400523072812
a = 250137278774864229623059201
b = 249563579992463717493803519
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 

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About benvitalis

math grad - Interest: Number theory
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