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		<title>Fun With Num3ers</title>
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		<item>
		<title>Using 9,9,9,9 to make 1-100</title>
		<link>http://benvitalenum3ers.wordpress.com/2013/05/24/using-9999-to-make-1-100/</link>
		<comments>http://benvitalenum3ers.wordpress.com/2013/05/24/using-9999-to-make-1-100/#comments</comments>
		<pubDate>Fri, 24 May 2013 19:27:23 +0000</pubDate>
		<dc:creator>benvitalis</dc:creator>
				<category><![CDATA[Math Beauty]]></category>
		<category><![CDATA[Number Puzzles]]></category>
		<category><![CDATA[1-20]]></category>
		<category><![CDATA[9 9 9 9]]></category>

		<guid isPermaLink="false">http://benvitalenum3ers.wordpress.com/?p=11775</guid>
		<description><![CDATA[Using &#160; 9, 9, 9, 9 &#160; and the basic operations make the numbers &#160; 1 &#160; to &#160; 100. You may also use decimal points. &#160; Here are the numbers &#160; 1 &#160; to &#160; 20: &#160; 1 &#160; &#8230; <a href="http://benvitalenum3ers.wordpress.com/2013/05/24/using-9999-to-make-1-100/">Continue reading <span class="meta-nav">&#8594;</span></a><img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=benvitalenum3ers.wordpress.com&#038;blog=31663778&#038;post=11775&#038;subd=benvitalenum3ers&#038;ref=&#038;feed=1" width="1" height="1" />]]></description>
				<content:encoded><![CDATA[<p>Using &nbsp; <strong>9, 9, 9, 9</strong> &nbsp; and the basic operations make the numbers &nbsp; <strong>1</strong> &nbsp; to &nbsp; <strong>100</strong>.</p>
<p>You may also use decimal points.<br />
&nbsp;<br />
Here are the numbers &nbsp; 1 &nbsp; to &nbsp; 20:<br />
&nbsp;<br />
1 &nbsp; = &nbsp; (9 + 9) / (9 + 9)<br />
2 &nbsp; = &nbsp; (9 + √9) / (9 &#8211; √9)<br />
3 &nbsp; = &nbsp; (9 + 9 + 9) / 9<br />
4 &nbsp; = &nbsp; (√9 * √9) / 9 &nbsp; + &nbsp; √9<br />
5 &nbsp; = &nbsp; (9 &#8211; √9) &nbsp; &#8211; &nbsp; (9 / 9)<br />
6 &nbsp; = &nbsp; (9 * √9) / 9 &nbsp; + &nbsp; √9<br />
7 &nbsp; = &nbsp; (9 / 9) &nbsp; + &nbsp; √9 &nbsp; + &nbsp; √9<br />
8 &nbsp; = &nbsp; (99) / 9 &nbsp; &#8211; &nbsp; √9<br />
9 &nbsp; = &nbsp; (√9 * √9) &nbsp; &#8211; &nbsp; (9 &#8211; 9) </p>
<p>10 &nbsp; = &nbsp; (√9 * √9) &nbsp; + &nbsp; (9 / 9)<br />
11 &nbsp; = &nbsp; 99 / (√9 * √9)<br />
12 &nbsp; = &nbsp; (9 * 9) / 9 &nbsp; + &nbsp; √9<br />
13 &nbsp; = &nbsp; 9 &nbsp; + &nbsp; √9 &nbsp; + &nbsp; (9 / 9)<br />
14 &nbsp; = &nbsp; (99) / 9 &nbsp; + &nbsp; √9<br />
15 &nbsp; = &nbsp; (√9 + √9) * √9 &nbsp; &#8211; &nbsp; √9<br />
16 &nbsp; = &nbsp; (9 / .9) &nbsp; + &nbsp; √9 &nbsp; + &nbsp; √9<br />
17 &nbsp; = &nbsp; (9 + 9) &nbsp; &#8211; &nbsp; (9 / 9)<br />
18 &nbsp; = &nbsp; ((√9 + √9) * 9) / √9<br />
19 &nbsp; = &nbsp; (9 + 9) &nbsp; + &nbsp; (9 / 9)<br />
20 &nbsp; = &nbsp; (99 / 9) &nbsp; + &nbsp; 9</p>
<p>&nbsp;<br />
Please extend the list<br />
&nbsp;<br />
&nbsp;</p>
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		<title>Triangle (5, 7, 8)</title>
		<link>http://benvitalenum3ers.wordpress.com/2013/05/23/triangle-5-7-8/</link>
		<comments>http://benvitalenum3ers.wordpress.com/2013/05/23/triangle-5-7-8/#comments</comments>
		<pubDate>Thu, 23 May 2013 21:01:17 +0000</pubDate>
		<dc:creator>benvitalis</dc:creator>
				<category><![CDATA[Math Beauty]]></category>
		<category><![CDATA[Number Puzzles]]></category>
		<category><![CDATA[Triangle]]></category>

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		<description><![CDATA[&#160; A triangle with sides of length &#160; 5, &#160; 7, &#160; and &#160; 8 Perimeter &#160; = &#160; 20 Area &#160; = &#160; 10 √3 &#160; ~ &#160; 17.3205 one of its angles measures 60 degrees: Applying the Law &#8230; <a href="http://benvitalenum3ers.wordpress.com/2013/05/23/triangle-5-7-8/">Continue reading <span class="meta-nav">&#8594;</span></a><img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=benvitalenum3ers.wordpress.com&#038;blog=31663778&#038;post=11773&#038;subd=benvitalenum3ers&#038;ref=&#038;feed=1" width="1" height="1" />]]></description>
				<content:encoded><![CDATA[<p>&nbsp;<br />
A triangle with sides of length &nbsp; <strong>5</strong>, &nbsp; <strong>7</strong>, &nbsp; and &nbsp; <strong>8</strong></p>
<p>Perimeter &nbsp; = &nbsp; 20<br />
Area &nbsp; = &nbsp; 10 √3 &nbsp; ~ &nbsp; 17.3205</p>
<p>one of its angles measures <strong>60</strong> degrees:</p>
<p>Applying the Law of cosines</p>
<p>7^2 &nbsp; = &nbsp; 8^2 &nbsp; + &nbsp; 5^2 &nbsp; &#8211; &nbsp; (2*8*5) cos(60)</p>
<p>The triangle has a 60 degrees angle between the sides of length &nbsp; 5 &nbsp; and &nbsp; 8.</p>
<p>&nbsp;</p>
<p>How many non-similar triangles with sides of integer length and angle 60 degrees can you find?<br />
&nbsp;<br />
&nbsp;<br />
&nbsp;</p>
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		<title>Primes p; n(p + n) is a square</title>
		<link>http://benvitalenum3ers.wordpress.com/2013/05/23/primes-p/</link>
		<comments>http://benvitalenum3ers.wordpress.com/2013/05/23/primes-p/#comments</comments>
		<pubDate>Thu, 23 May 2013 19:52:13 +0000</pubDate>
		<dc:creator>benvitalis</dc:creator>
				<category><![CDATA[Number Puzzles]]></category>
		<category><![CDATA[Prime Numbers]]></category>

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		<description><![CDATA[Consider the first few prime numbers:           2,   3,  5,  7,  11,  13,  17,  19,  23,  29,  31,  37 And   f(p) = n(p + n),     where  p  is an odd prime and &#8230; <a href="http://benvitalenum3ers.wordpress.com/2013/05/23/primes-p/">Continue reading <span class="meta-nav">&#8594;</span></a><img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=benvitalenum3ers.wordpress.com&#038;blog=31663778&#038;post=11766&#038;subd=benvitalenum3ers&#038;ref=&#038;feed=1" width="1" height="1" />]]></description>
				<content:encoded><![CDATA[<p>Consider the first few prime numbers:           2,   3,  5,  7,  11,  13,  17,  19,  23,  29,  31,  37</p>
<p>And  <strong> f(p) = n(p + n)</strong>,     where  <strong>p</strong>  is an odd prime</p>
<p>and find  <strong>n</strong>  so that  <strong>f(p)</strong>  is a square</p>
<p>1(3 + 1)  =  4  =  <strong>2^2</strong>                                                        4(5 + 4)  =  36  =  <strong>6^2</strong><br />
9(7 + 9)  =  144  =  <strong>12^2</strong></p>
<p>25(11 + 25)  =  900  =  <strong>30^2</strong>                                 36(13 + 36)  =  1764  =  <strong>42^2</strong><br />
64(17 + 64)  =  5184  =  <strong>72^2</strong>                                81(19 + 81)  =  8100  =  <strong>90^2</strong><br />
121(23 + 121)  =  17424  =  <strong>132^2</strong>                  196(29 + 196)  =  44100  =  <strong>210^2</strong><br />
225(31 + 225)  =  57600  =  <strong>240^2</strong>              324(37 + 324)  =  116964  =  <strong>342^2</strong></p>
<p>&nbsp;</p>
<p>These results indicate that there exists a positive integer &nbsp; n &nbsp; such that &nbsp; n(p + n) &nbsp; is a perfect square</p>
<p>Could you show that for any odd prime p there&#8217;s a unique positive integer &nbsp; n &nbsp; such that &nbsp;<br />
n(p + n) &nbsp; is a perfect square?</p>
<p>&nbsp;<br />
&nbsp;<br />
&nbsp;<br />
&nbsp;<br />
&nbsp;</p>
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		<item>
		<title>Using 1,2,3,4,5 only once to make 1 &#8211; 100</title>
		<link>http://benvitalenum3ers.wordpress.com/2013/05/22/using-12345-only-once-to-make-1-100/</link>
		<comments>http://benvitalenum3ers.wordpress.com/2013/05/22/using-12345-only-once-to-make-1-100/#comments</comments>
		<pubDate>Wed, 22 May 2013 23:37:46 +0000</pubDate>
		<dc:creator>benvitalis</dc:creator>
				<category><![CDATA[Math Beauty]]></category>
		<category><![CDATA[Number Puzzles]]></category>
		<category><![CDATA[1 2 3 4 5]]></category>
		<category><![CDATA[1-100]]></category>

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		<description><![CDATA[Game: Using  1, 2, 3, 4, 5  only once and the basic operations (+, -, * , / , !) to make all the numbers from  1  to  100 &#160; 0 = 5 + 3 &#8211; (4*2/1)       &#8230; <a href="http://benvitalenum3ers.wordpress.com/2013/05/22/using-12345-only-once-to-make-1-100/">Continue reading <span class="meta-nav">&#8594;</span></a><img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=benvitalenum3ers.wordpress.com&#038;blog=31663778&#038;post=11731&#038;subd=benvitalenum3ers&#038;ref=&#038;feed=1" width="1" height="1" />]]></description>
				<content:encoded><![CDATA[<p>Game:</p>
<p>Using  <strong>1, 2, 3, 4, 5</strong>  only once and the basic operations (+, -, * , / , !) to make all the numbers from  1  to  100<br />
&nbsp;</p>
<p><strong>0</strong> = 5 + 3 &#8211; (4*2/1)                                                <strong>5</strong> = 4*3/(5 &#8211; 1) + 2<br />
<strong>1</strong> = (4 + 5)/3 &#8211; 2*1                                                 <strong>6</strong> = 4*3/(5 &#8211; (1 + 2))<br />
<strong>2</strong> = (3 + 5 &#8211; 4)/2*1                                               <strong> 7</strong> = (3*2/1) + 5 &#8211; 4<br />
<strong>3</strong> = 4 + 5 &#8211; (3*2/1)                                                 <strong>8</strong> = 4*2/(5 &#8211; (3 + 1))<br />
<strong>4</strong> = (3 + 5)/( 4- 2*1)                                              <strong>9</strong> = 4*3/1 &#8211; 5 + 2</p>
<p><strong>10</strong> = 5*(3 &#8211; 4/2 + 1)                                             <strong>15</strong> = 5*(4 &#8211; 3 + 2)/1<br />
<strong>11</strong> = 5*2 + 4/2 &#8211; 1                                                 <strong>16</strong> = (3 + 5) * (4 &#8211; 2)/1<br />
<strong>12</strong> = 5*2 + 4/(3 &#8211; 1)                                             <strong>17</strong> = 5*3 + 4 &#8211; 2/1<br />
<strong>13</strong> = 5*3/1 &#8211; 4 + 2                                                <strong>18</strong> = 3 * (5 + 4/2 &#8211; 1)<br />
<strong>14</strong> = 4*(5 + 3 &#8211; 1)/2                                             <strong>19</strong> = 5*4 &#8211; 3/(2 + 1)</p>
<p><strong>20</strong> = (3 + 4/2 &#8211; 1) * 5                                          <strong>25</strong> = (4 + 3 &#8211; 2/1)*5<br />
<strong>21</strong> = (4 + 5 &#8211; 2) * 3/1                                           <strong>26</strong> = 4! + 2/(3! &#8211; 5*1)<br />
<strong>22</strong> = (3! + 5) * (4 &#8211; 2/1)                                      <strong>27</strong> = (4 + 2)*5 &#8211; 3/1<br />
<strong>23</strong> = (5*4 + 3)/(2 &#8211; 1)                                          <strong>28</strong> = 4!/(5 &#8211; 2)!*(3! + 1)<br />
<strong>24</strong> = (3 + 5 &#8211; 2/1)*4                                            <strong> 29</strong> = 5*3! &#8211; 4/2 + 1</p>
<p><strong>30</strong> = (5 + 3)*4 &#8211; 2/1                                             <strong>35</strong> = 5*(4!/3 &#8211; 2 + 1)<br />
<strong>31</strong> = 5*3! + 4/2 &#8211; 1                                                <strong>36</strong> = 3!*(5 + 4/2 &#8211; 1)<br />
<strong>32</strong> = 5*3! + 4/1 &#8211; 2                                               <strong>37</strong> = 5*(4!/3 &#8211; 1) + 2<br />
<strong>33</strong> = 5*(4 + 3) &#8211; 2/1                                              <strong>38</strong> =  5!/3 &#8211; 4 + 2*1<br />
<strong>34</strong> = 5*3! + 4/(2 &#8211; 1)                                            <strong>39</strong> = 2*(5! &#8211; 4 + 1)/3!</p>
<p><strong>40</strong> = 5!/(4 &#8211; 3 + 2) * 1                                         <strong>45</strong> = 5*(4!/3 + 2 &#8211; 1)<br />
<strong>41</strong> = 2*(5! + 4 &#8211; 1)/3!                                           <strong>46</strong> =  5*(4!/2 &#8211; 3) + 1<br />
<strong>42</strong> = 5!/3 + 4 &#8211; 2*1                                               <strong>47</strong> =  5!/3 + 4*2 &#8211; 1<br />
<strong>43</strong> = (4! &#8211; 2*5)*3 + 1                                            <strong>48</strong> =  (1 + (5 &#8211; 3)/2)*4!<br />
<strong>44</strong> = 4 * (3! + 5/(2 &#8211; 1))                                       <strong>49</strong> = (3! + 1)*(4!/2 &#8211; 5)</p>
<p><strong>50</strong> = (5!/4 &#8211; 3! + 1) * 2                                        <strong>55</strong> = 5!*2/4 &#8211; 3! + 1<br />
<strong>51</strong> = 1 * (5! + 3! &#8211; 4!)/2                                       <strong>56</strong> = (5 + 1)!/(2*3!) &#8211; 4<br />
<strong>52</strong> = 4!*(2 + 1) &#8211; 5!/3!                                         <strong>57</strong> = (5!/(2 + 4) &#8211; 1)*3<br />
<strong>53</strong> = 5!*2/4 &#8211; (3! + 1)                                           <strong>58</strong> = (5 + 1)!/(4*3) &#8211; 2<br />
<strong>54</strong> = 1*(5! &#8211; 4!)/2 + 3!                                         <strong>59</strong> = 5!/2 + 3 &#8211; 4*1</p>
<p><strong>60</strong> = 5!*(3 &#8211; 2 + 1)/4                                            <strong>65</strong> = 2*(5! &#8211; 4!)/3 + 1<br />
<strong>61</strong> = 5!*(4 &#8211; 3)/2 + 1                                             <strong>66</strong> = 4!*(5 + 1)/2 &#8211; 3!<br />
<strong>62</strong> = 5!/3 + 4! &#8211; 2*1                                              <strong>67</strong> = 3*4! + 5/(1 &#8211; 2)<br />
<strong>63</strong> = 5!/(4 &#8211; 2) + 3*1                                            <strong>68</strong> = 5!/(3 &#8211; 1) + 4*2<br />
<strong>64</strong> = 1*(5! &#8211; 4)/2 + 3!                                           <strong>69</strong> = 5!/2 + (4 &#8211; 1)*3</p>
<p><strong>70</strong> = 3*4! + (1 &#8211; 5)/2                                            <strong>75</strong> = 2*5!/3 &#8211; (4 + 1)<br />
<strong>71</strong> = 5!/2 + 4*3 &#8211; 1                                                <strong>76</strong> = 4!*3!/2 + 5 &#8211; 1<br />
<strong>72</strong> = (2 + 1) * (5!/4 &#8211; 3!)                                     <strong>77</strong> = 3*4!/(2 &#8211; 1) + 5<br />
<strong>73</strong> = 3*(4! + 2) &#8211; 5/1                                            <strong>78</strong> = 3*(4! + (5 &#8211; 1)/2)<br />
<strong>74</strong> = 4*5!/3! &#8211; (2 + 1)!                                         <strong>79</strong> = 4*5!/3! &#8211; 2 + 1</p>
<p><strong>80</strong> = 5!*(3! &#8211; 4)/(1 + 2)                                       <strong>85</strong> = 3*(4! + 5) &#8211; 2/1<br />
<strong>81</strong> = 4*5!/3! + 2 &#8211; 1                                               <strong>86</strong> = 3!*(4! + 5)/2 &#8211; 1<br />
<strong>82</strong> = 4*(5!/3! + 1) &#8211; 2                                           <strong>87</strong> = 4*(5!/3! + 2) &#8211; 1<br />
<strong>83</strong> = 2*5!/3 + 4 &#8211; 1                                              <strong> 88</strong> = (5 + 3) * (4!/2 &#8211; 1)<br />
<strong>84</strong> = 3*5!/4 &#8211; (2 + 1)!                                          <strong>89</strong> = (5!*3)/4 &#8211; 2 + 1</p>
<p><strong>90</strong> = (4 + 1) * (5!/3! &#8211; 2)                                     <strong>95</strong> = (5!*4)/(2 + 3) &#8211; 1<br />
<strong>91</strong> = (5!*3)/4 + 2 &#8211; 1                                             <strong>96</strong> = (5! &#8211; 4!) * 3/(2 + 1)<br />
<strong>92</strong> = 5*(4! &#8211; 3!) + 2/1                                      <strong>   97</strong> = (3!)!/5 + 1 &#8211; 2*4!<br />
<strong>93</strong> = 5! &#8211; (4! + 1*3!/2)                                        <strong>98</strong> = (5!*4)/(3! &#8211; 1) + 2<br />
<strong>94</strong> = 5! &#8211; (4*3! + 2/1)                                          <strong>99</strong> =  5! + 3!/2 &#8211; 4!*1</p>
<p><strong>100</strong> = 5*(4! &#8211; 3! + 2)/1</p>
<p>&nbsp;<br />
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&nbsp;</p>
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		<title>Num3ers with repeated digits divisible by a prime they contain</title>
		<link>http://benvitalenum3ers.wordpress.com/2013/05/22/num3ers-with-repeated-digits-divisible-by-a-prime-they-contain/</link>
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		<pubDate>Wed, 22 May 2013 20:33:08 +0000</pubDate>
		<dc:creator>benvitalis</dc:creator>
				<category><![CDATA[Uncategorized]]></category>

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		<description><![CDATA[Start with a 2-digit prime number 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97 and find numbers that repeat the digits of the chosen prime and divisible &#8230; <a href="http://benvitalenum3ers.wordpress.com/2013/05/22/num3ers-with-repeated-digits-divisible-by-a-prime-they-contain/">Continue reading <span class="meta-nav">&#8594;</span></a><img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=benvitalenum3ers.wordpress.com&#038;blog=31663778&#038;post=11751&#038;subd=benvitalenum3ers&#038;ref=&#038;feed=1" width="1" height="1" />]]></description>
				<content:encoded><![CDATA[<p>Start with a 2-digit prime number</p>
<p>11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97</p>
<p>and find numbers that repeat the digits of the chosen prime and divisible by this prime<br />
&nbsp;</p>
<p>For example,</p>
<p><strong>19</strong>, &nbsp; 1919</p>
<p><strong>11191</strong> &nbsp; is divisible by 19, &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; 11191 &nbsp; = &nbsp; 19 * 19 * 31</p>
<p><strong>17</strong>, &nbsp; 1717</p>
<p><strong>22333</strong> &nbsp; = &nbsp; 23 * 971<br />
<strong>44333</strong> &nbsp; = &nbsp; 43 * 1031<br />
<strong>555533333</strong> &nbsp; = &nbsp; 53 * 10481761</p>
<p><strong>13</strong>, &nbsp; 1131, &nbsp; 1313, &nbsp; 3133</p>
<p>Divisible by &nbsp; 11:<br />
<strong>11</strong>, &nbsp; 1111, &nbsp; 111111, &nbsp; 11111111, &nbsp; 1111111111, &#8230;</p>
<p>N.B. &nbsp; numbers of the form &nbsp; <strong>abababab&#8230;</strong> &nbsp;  are <U>not</U> the examples I&#8217;m looking for. </p>
<p> E.g. &nbsp; 1313, &nbsp; 131313&#8230; &nbsp; 1717, &nbsp; 171717&#8230;, &nbsp; 191919&#8230;  </p>
<p>What I consider to be good examples are:</p>
<p>11191, &nbsp; 1131, &nbsp; 3133, &nbsp; 22333, &nbsp; 44333, &nbsp; 555533333</p>
<p>Find larger ones (if possible) and find other numbers using the remaining 2-digit numbers.</p>
<p>&nbsp;<br />
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&nbsp;</p>
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		<title>Concatenation &#124; (x &#8211; y + z)^3 = x &#124;&#124; y &#124;&#124; z</title>
		<link>http://benvitalenum3ers.wordpress.com/2013/05/21/concatenation-x-y-z3-x-y-z/</link>
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		<pubDate>Tue, 21 May 2013 22:28:58 +0000</pubDate>
		<dc:creator>benvitalis</dc:creator>
				<category><![CDATA[Number Puzzles]]></category>
		<category><![CDATA[Concatenation]]></category>
		<category><![CDATA[Cubes]]></category>

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		<description><![CDATA[Older post:   Concatenation: x&#124;&#124;y&#124;&#124;z = x^3 + y^3 + z^3 &#160; Find integers   x,   y   and   z   such that &#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160; (x &#8211; y + z)^3   =   x &#124;&#124; y &#124;&#124; z &#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160; &#8230; <a href="http://benvitalenum3ers.wordpress.com/2013/05/21/concatenation-x-y-z3-x-y-z/">Continue reading <span class="meta-nav">&#8594;</span></a><img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=benvitalenum3ers.wordpress.com&#038;blog=31663778&#038;post=11734&#038;subd=benvitalenum3ers&#038;ref=&#038;feed=1" width="1" height="1" />]]></description>
				<content:encoded><![CDATA[<p>Older post:   <a title="numbers" href="http://benvitalenum3ers.wordpress.com/2013/03/14/concatenation-xyz-x3-y3-z3/">Concatenation: x||y||z = x^3 + y^3 + z^3</a></p>
<p>&nbsp;</p>
<p>Find integers   <strong>x,   y</strong>   and   <strong>z</strong>   such that</p>
<p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <strong>(x &#8211; y + z)^3   =   x || y || z</strong></p>
<p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <strong>(-x + y + z)^3   =   x || y || z</strong></p>
<p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <strong>(x + y + z)^3   =   x || y || z</strong></p>
<p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <strong>(x + y &#8211; z)^3   =   x || y || z</strong></p>
<p>&nbsp;</p>
<p>For example,</p>
<p><strong>(9 + 11 + 25)^3 &nbsp;&nbsp; = &nbsp;&nbsp; 91125 &nbsp;&nbsp; = &nbsp;&nbsp; 9 || 11 || 25 &nbsp;&nbsp; = &nbsp;&nbsp; 45^3</strong></p>
<p><strong>(786 &#8211; 330 + 467)^3   =   786330467   =   786 || 330 || 467</strong></p>
<p><strong>(188 &#8211; 132 + 517)^3 &nbsp;&nbsp; = &nbsp;&nbsp; 188132517 &nbsp;&nbsp; = &nbsp;&nbsp;  188 || 132 || 517</strong></p>
<p><strong>(258 &#8211; 474 + 853)^3 &nbsp;&nbsp; = &nbsp;&nbsp; 258474853 &nbsp;&nbsp; = &nbsp;&nbsp; 258 || 474 || 853</strong></p>
<p><strong>(-360 + 944 + 128)^3 &nbsp;&nbsp; = &nbsp;&nbsp; 360944128 &nbsp;&nbsp; = &nbsp;&nbsp; 360 || 944 || 128</strong></p>
<p>&nbsp;<br />
&nbsp;<br />
And,</p>
<p><em>(13 &#8211; 3 + 1)^3 &nbsp; = &nbsp; 1331<br />
(103 &#8211; 03 + 01)^3 &nbsp; = &nbsp; 1030301<br />
(1003 &#8211; 003 + 001)^3 &nbsp; = &nbsp; 1003003001<br />
(10003 &#8211; 0003 + 0001)^3 &nbsp; = &nbsp; 1000300030001<br />
(100003 &#8211; 00003 + 00001)^3 &nbsp; = &nbsp; 1000030000300001<br />
(1000003 &#8211; 000003 + 000001)^3 &nbsp; = &nbsp; 1000003000003000001</em></p>
<p> <em>(106 &#8211; 12 + 08)^3 &nbsp; = &nbsp; 1061208<br />
(1006 &#8211; 012 + 008)^3 &nbsp; = &nbsp; 1006012008<br />
(10006 &#8211; 0012 + 0008)^3 &nbsp; = &nbsp; 1000600120008<br />
(100006 &#8211; 00012 + 00008)^3 &nbsp; = &nbsp; 1000060001200008<br />
(1000006 &#8211; 000012 + 000008)^3 &nbsp; = &nbsp; 1000006000012000008</em>  </p>
<p>&nbsp;<br />
&nbsp;<br />
<strong>@InfinitelyManic</strong> found:</p>
<p>(5 + 1 + 2)^3 &nbsp; = &nbsp; 512 &nbsp; = &nbsp; 5 || 1 || 2<br />
(3 &#8211; 723 + 875)^3 &nbsp; = &nbsp; 3723875 &nbsp; = &nbsp; 3 || 723 || 875<br />
(9 + 73 &#8211; 36)^3 &nbsp; = &nbsp; 97336 &nbsp; = &nbsp; 9 || 73 || 36<br />
(9 &#8211; 129 + 329)^3 &nbsp; = &nbsp; 9129329 &nbsp; = &nbsp; 9 || 129 || 329<br />
(19 + 51 &#8211; 12)^3 &nbsp; = &nbsp; 195112 &nbsp; = &nbsp; 19 || 51 || 12<br />
 (20 &#8211; 570 + 824)^3 &nbsp; = &nbsp; 20570824 &nbsp; = &nbsp; 20 || 570 || 824<br />
 (23 &#8211; 393 + 656)^3 &nbsp; = &nbsp; 23393656 &nbsp; = &nbsp; 23 || 393 || 656<br />
 (23 &#8211; 639 + 903)^3 &nbsp; = &nbsp; 23639903 &nbsp; = &nbsp; 23 || 639 || 903<br />
 (43 &#8211; 243 + 551)^3 &nbsp; = &nbsp; 43243551 &nbsp; = &nbsp; 43|| 243 || 551<br />
 (45 + 65 &#8211; 33)^3 &nbsp; = &nbsp; 456533 &nbsp; = &nbsp; 45 || 65 || 33<br />
 (48 &#8211; 228 + 544)^3 &nbsp; = &nbsp; 48228544 &nbsp; = &nbsp; 48 || 228 || 544<br />
 (78 &#8211; 402 + 752)^3 &nbsp; = &nbsp; 78402752 &nbsp; = &nbsp; 78 || 402 || 752<br />
 (-123 + 263 + 91)^3 &nbsp; = &nbsp; 12326391 &nbsp; = &nbsp; 123 || 263 || 91<br />
&nbsp;<br />
&nbsp;<br />
&nbsp;</p>
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		<title>Using Primes 2,3,5,7 only once to make 1-100</title>
		<link>http://benvitalenum3ers.wordpress.com/2013/05/21/using-primes-2357-only-once-to-make-1-100/</link>
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		<pubDate>Tue, 21 May 2013 18:14:45 +0000</pubDate>
		<dc:creator>benvitalis</dc:creator>
				<category><![CDATA[Number Puzzles]]></category>
		<category><![CDATA[1-100]]></category>

		<guid isPermaLink="false">http://benvitalenum3ers.wordpress.com/?p=11728</guid>
		<description><![CDATA[Game: You can use the primes &#160; 2, 3, 5, 7 &#160; and the basic operations &#160; +, -, *, / &#160; and &#160; ! &#160; (factorial) only once to make numbers from &#160; 1 &#160; to &#160; 100. &#160; &#8230; <a href="http://benvitalenum3ers.wordpress.com/2013/05/21/using-primes-2357-only-once-to-make-1-100/">Continue reading <span class="meta-nav">&#8594;</span></a><img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=benvitalenum3ers.wordpress.com&#038;blog=31663778&#038;post=11728&#038;subd=benvitalenum3ers&#038;ref=&#038;feed=1" width="1" height="1" />]]></description>
				<content:encoded><![CDATA[<p><strong>Game:</strong></p>
<p>You can use the primes &nbsp; <strong>2, 3, 5, 7</strong> &nbsp; and the basic operations &nbsp; +, -, *, / &nbsp; and &nbsp; ! &nbsp; (factorial) only once to make numbers from &nbsp; <strong>1</strong> &nbsp; to &nbsp; <strong>100</strong>.<br />
&nbsp;</p>
<p>N.B. &nbsp;&nbsp; you may use decimal points<br />
&nbsp;</p>
<p>For example,</p>
<p><strong>0</strong> &nbsp; = &nbsp; (7 + 3)/5 &#8211; 2<br />
<strong>1</strong> &nbsp; = &nbsp; (7 &#8211; 5) &#8211; (3 &#8211; 2) &nbsp;&nbsp;&nbsp; or &nbsp;&nbsp;&nbsp; 1 &nbsp; = &nbsp; (3 * 5) &#8211; (2 * 7)<br />
<strong>2</strong> &nbsp; = &nbsp; 7 &#8211; 3! + (3 &#8211; 2)<br />
<strong>3</strong> &nbsp; = &nbsp; (7 &#8211; 2) &#8211; (5 &#8211; 3)<br />
<strong>4</strong> &nbsp; = &nbsp; 2*3 &#8211; (7 &#8211; 5)</p>
<p>&nbsp;<br />
How many other numbers can you express?<br />
&nbsp;<br />
&nbsp;<br />
&nbsp;<br />
&nbsp;<br />
&nbsp;<br />
&nbsp;</p>
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		<title>Non-palindrome multiplied by its reverse is a square</title>
		<link>http://benvitalenum3ers.wordpress.com/2013/05/21/non-palindrome-multiplied-by-its-reverse-is-a-square/</link>
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		<pubDate>Tue, 21 May 2013 08:57:25 +0000</pubDate>
		<dc:creator>benvitalis</dc:creator>
				<category><![CDATA[Math Beauty]]></category>
		<category><![CDATA[Number Puzzles]]></category>
		<category><![CDATA[Non-palindrome]]></category>
		<category><![CDATA[Squares]]></category>

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		<description><![CDATA[&#160; For example, 288 &#160; is a non-palindrome and a non-square number. Its reverse is: &#160;&#160;&#160; Rev (288) &#160; = &#160; 882 and, 288 &#160; * &#160; 882 &#160; = &#160; 254016 &#160; = &#160; 504^2 &#160; is a perfect &#8230; <a href="http://benvitalenum3ers.wordpress.com/2013/05/21/non-palindrome-multiplied-by-its-reverse-is-a-square/">Continue reading <span class="meta-nav">&#8594;</span></a><img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=benvitalenum3ers.wordpress.com&#038;blog=31663778&#038;post=11722&#038;subd=benvitalenum3ers&#038;ref=&#038;feed=1" width="1" height="1" />]]></description>
				<content:encoded><![CDATA[<p>&nbsp;<br />
For example,</p>
<p><strong>288</strong> &nbsp; is a <U>non-palindrome</U> and a <U>non-square</U> number.</p>
<p>Its reverse is: &nbsp;&nbsp;&nbsp; Rev (288) &nbsp; = &nbsp; 882</p>
<p>and,</p>
<p>288 &nbsp; * &nbsp; 882 &nbsp; = &nbsp; 254016 &nbsp; = &nbsp; <strong>504^2</strong> &nbsp; is a perfect square.</p>
<p>&nbsp;</p>
<p>&nbsp;<br />
882 * 288 &nbsp; = &nbsp; 504^2<br />
80802 * 20808 &nbsp; = &nbsp; 41004^2<br />
8008002 * 2008008 &nbsp; = &nbsp; 4010004^2<br />
800080002 * 200080008 &nbsp; = &nbsp; 400100004^2<br />
80000800002 * 20000800008 &nbsp; = &nbsp; 40001000004^2<br />
8000008000002 * 2000008000008 &nbsp; = &nbsp; 4000010000004^2</p>
<p>and so on.</p>
<p>&nbsp;</p>
<p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; &#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;<br />
&nbsp;<br />
David @InfinitelyManic found :</p>
<p>528 * 825 &nbsp; = &nbsp; 660^2<br />
768 * 867 &nbsp; = &nbsp; 816^2<br />
1584 * 4851 &nbsp; = &nbsp; 2772^2<br />
2178 * 8712 &nbsp; = &nbsp; 4356^2<br />
10989 * 98901 &nbsp; = &nbsp; 32967^2<br />
13104 * 40131 &nbsp; = &nbsp; 22932^2<br />
14544 * 44541 &nbsp; = &nbsp; 25452^2<br />
15984 * 48951 &nbsp; = &nbsp; 27972^2<br />
20808 * 80802 &nbsp; = &nbsp; 41004^2<br />
21978 * 87912 &nbsp; = &nbsp; 43956^2<br />
26208 * 80262 &nbsp; = &nbsp; 45864^2<br />
27648 * 84672 &nbsp; = &nbsp; 48384^2<br />
27848 * 84872 &nbsp; = &nbsp; 48616^2<br />
36828 * 82863 &nbsp; = &nbsp; 55242^2<br />
48139 * 93184 &nbsp; = &nbsp; 66976^2<br />
48951 * 15984 &nbsp; = &nbsp; 27972^2<br />
49686 * 68694 &nbsp; = &nbsp; 58422^2<br />
57399 * 99375 &nbsp; = &nbsp; 75525^2<br />
&nbsp;<br />
&nbsp;<br />
&nbsp;<br />
&nbsp;<br />
&nbsp;</p>
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		<title>DigitProduct and Sum of prime factors of numbers</title>
		<link>http://benvitalenum3ers.wordpress.com/2013/05/20/digitproduct-and-sum-of-prime-factors-of-numbers/</link>
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		<pubDate>Mon, 20 May 2013 17:10:42 +0000</pubDate>
		<dc:creator>benvitalis</dc:creator>
				<category><![CDATA[Math Beauty]]></category>
		<category><![CDATA[Number Puzzles]]></category>
		<category><![CDATA[DigitProduct]]></category>
		<category><![CDATA[Prime Factors]]></category>

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		<description><![CDATA[(1) Integers such that the sum of prime factors equal the product of the digits of those integers: &#160; The prime factors of   18   are:                           &#8230; <a href="http://benvitalenum3ers.wordpress.com/2013/05/20/digitproduct-and-sum-of-prime-factors-of-numbers/">Continue reading <span class="meta-nav">&#8594;</span></a><img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=benvitalenum3ers.wordpress.com&#038;blog=31663778&#038;post=11684&#038;subd=benvitalenum3ers&#038;ref=&#038;feed=1" width="1" height="1" />]]></description>
				<content:encoded><![CDATA[<p><strong>(1)</strong></p>
<p>Integers such that the sum of prime factors equal the product of the digits of those integers:<br />
&nbsp;</p>
<p>The prime factors of   <strong>18</strong>   are:                           2 * 3 * 3<br />
The sum is:                                                                 2  +  3  +  3  =  <strong>8</strong><br />
DigitProduct (18)  =                                                1 * 8  =  <strong>8</strong></p>
<p>The prime factors of  <strong>25</strong>  are:                             5 * 5<br />
The sum is:                                                                  5  +  5  =  <strong>10</strong><br />
DigitProduct (25)  =                                                2 * 5  =  <strong>10</strong></p>
<p>&nbsp;</p>
<p>Find other examples.<br />
&nbsp;</p>
<p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; &#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;<br />
&nbsp;</p>
<p><strong>(2)</strong></p>
<p>Integers such that the sum of prime factors and the product of the digits are perfect powers:<br />
&nbsp;<br />
The prime factors of  <strong>14</strong>  are:                              2 * 7<br />
The sum is:                                                                  2  +  7  =  9  =  <strong>3^2</strong><br />
DigitProduct (14) =                                                 1 * 4  =  <strong>2^2</strong></p>
<p>The prime factors of  <strong>24</strong>  are:                             2 * 2 * 2 * 3<br />
The sum is:                                                                  2  +  2  +  2  +  3  =  9  =  <strong>3^2</strong><br />
DigitProduct (24) =                                                 2 * 4  =  8  = <strong> 2^3</strong></p>
<p>The prime factors of  <strong>39</strong>  are:                             3 * 13<br />
The sum is:                                                                  3  +  13  =  16  =  <strong>4^2</strong><br />
DigitProduct (39) =                                                 3 * 9  =  27  =  <strong>3^3</strong></p>
<p>The prime factors of  <strong>55</strong>  are:                             5 * 11<br />
The sum is:                                                                  5  +  11  =  16  =  <strong>4^2</strong><br />
DigitProduct (55) =                                                 5 * 5  =  <strong>5^2</strong></p>
<p>The prime factors of  <strong>66</strong>  are:                             2 * 3 * 11<br />
The sum is:                                                                  2  +  3  +  11  =  <strong>4^2</strong><br />
DigitProduct (66) =                                                 6 * 6  = <strong> 6^2</strong></p>
<p>The prime factors of  <strong>94</strong>  are:                             2 * 47<br />
The sum is:                                                                  2  +  47  =  49  =  <strong>7^2</strong><br />
DigitProduct (94) =                                                 9 * 4  =  36  = <strong> 6^2</strong></p>
<p>&nbsp;<br />
Find other such integers.<br />
&nbsp;</p>
<p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; &#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;<br />
&nbsp;</p>
<p><strong>(3)</strong></p>
<p>The product of the digits of &nbsp; <strong>236</strong> &nbsp; is the reverse of the sum of its prime factors:<br />
&nbsp;</p>
<p>The prime factors of  <strong>236</strong>  are:                          2 * 2 * 59<br />
The sum is:                                                                  2  +  2  +  59  =  <strong>63</strong><br />
DigitProduct (236) =                                              2 * 3 * 6  =  <strong>36</strong></p>
<p>&nbsp;<br />
Find other integers with the same property<br />
&nbsp;</p>
<p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; &#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;<br />
&nbsp;<br />
<strong>(4)</strong></p>
<p><strong>Digit Permutations:</strong></p>
<p>The product of the digits of &nbsp; <strong>2537</strong> &nbsp; is a digit permutation of the sum of its prime factors</p>
<p>2537 &nbsp; = &nbsp; 43 * 59</p>
<p>Sum of prime factors: &nbsp;&nbsp;&nbsp; 43 + 59 &nbsp; = &nbsp; <strong>102</strong></p>
<p>DigitProduct (2537) &nbsp; = &nbsp; 2 * 5 * 3 * 7 &nbsp; = &nbsp; <strong>210</strong></p>
<p><strong>2537</strong> &nbsp; is also a multiple of a prime containing only prime digits &nbsp; (2, 3, 5, 7)</p>
<p>&nbsp;<br />
&nbsp;<br />
&nbsp;</p>
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		<title>3-digit Num3ers w/ consecutive digits</title>
		<link>http://benvitalenum3ers.wordpress.com/2013/05/20/3-digit-num3ers-w-consecutive-digits/</link>
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		<pubDate>Mon, 20 May 2013 00:12:22 +0000</pubDate>
		<dc:creator>benvitalis</dc:creator>
				<category><![CDATA[Math Beauty]]></category>
		<category><![CDATA[3-digit Numbers]]></category>

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		<description><![CDATA[123 + 132 + 213 + 231 + 312 + 321 = 1332 (123 + 132 + 213 + 231 + 312 + 321)/2 = 666 (123 + 132 + 213 + 231 + 312 + 321)/3 = 444 (123 &#8230; <a href="http://benvitalenum3ers.wordpress.com/2013/05/20/3-digit-num3ers-w-consecutive-digits/">Continue reading <span class="meta-nav">&#8594;</span></a><img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=benvitalenum3ers.wordpress.com&#038;blog=31663778&#038;post=11676&#038;subd=benvitalenum3ers&#038;ref=&#038;feed=1" width="1" height="1" />]]></description>
				<content:encoded><![CDATA[<p><strong>123 + 132 + 213 + 231 + 312 + 321 = 1332</strong></p>
<p>(123 + 132 + 213 + 231 + 312 + 321)/2 = 666<br />
(123 + 132 + 213 + 231 + 312 + 321)/3 = 444<br />
(123 + 132 + 213 + 231 + 312 + 321)/4 = 333<br />
(123 + 132 + 213 + 231 + 312 + 321)/6 = 222<br />
(123 + 132 + 213 + 231 + 312 + 321)/9 = 148</p>
<p><strong>234 + 243 + 324 + 342 + 423 + 432 = 1998</strong></p>
<p>(234 + 243 + 324 + 342 + 423 + 432)/2 = 999<br />
(234 + 243 + 324 + 342 + 423 + 432)/3 = 666<br />
(234 + 243 + 324 + 342 + 423 + 432)/6 = 333<br />
(234 + 243 + 324 + 342 + 423 + 432)/9 = 222</p>
<p><strong>345 + 354 + 435 + 453 + 534 + 543 = 2664</strong></p>
<p>(345 + 354 + 435 + 453 + 534 + 543)/2 = 1332<br />
(345 + 354 + 435 + 453 + 534 + 543)/3 = 888<br />
(345 + 354 + 435 + 453 + 534 + 543)/4 = 666<br />
(345 + 354 + 435 + 453 + 534 + 543)/6 = 444<br />
(345 + 354 + 435 + 453 + 534 + 543)/8 = 333<br />
(345 + 354 + 435 + 453 + 534 + 543)/9 = 296</p>
<p><strong>456 + 465 + 546 + 564 + 645 + 654 = 3330</strong></p>
<p>(456 + 465 + 546 + 564 + 645 + 654)/2 = 1665<br />
(456 + 465 + 546 + 564 + 645 + 654)/3 = 1110<br />
(456 + 465 + 546 + 564 + 645 + 654)/5 = 666<br />
(456 + 465 + 546 + 564 + 645 + 654)/6 = 555<br />
(456 + 465 + 546 + 564 + 645 + 654)/9 = 370</p>
<p><strong>567 + 576 + 657 + 675 + 756 + 765 = 3996</strong></p>
<p>(567 + 576 + 657 + 675 + 756 + 765)/2 = 1998<br />
(567 + 576 + 657 + 675 + 756 + 765)/3 = 1332<br />
(567 + 576 + 657 + 675 + 756 + 765)/4 = 999<br />
(567 + 576 + 657 + 675 + 756 + 765)/6 = 666<br />
(567 + 576 + 657 + 675 + 756 + 765)/9 = 444</p>
<p><strong>678 + 687 + 768 + 786 + 867 + 876  = 4662</strong></p>
<p>(678 + 687 + 768 + 786 + 867 + 876)/2 = 2331<br />
(678 + 687 + 768 + 786 + 867 + 876)/3 = 1554<br />
(678 + 687 + 768 + 786 + 867 + 876)/6 = 777<br />
(678 + 687 + 768 + 786 + 867 + 876)/7 = 666<br />
(678 + 687 + 768 + 786 + 867 + 876)/9 = 518</p>
<p><strong>789 + 798 + 879 + 897 + 978 + 987  = 5328</strong></p>
<p>(789 + 798 + 879 + 897 + 978 + 987)/2 = 2664<br />
(789 + 798 + 879 + 897 + 978 + 987)/3 = 1776<br />
(789 + 798 + 879 + 897 + 978 + 987)/4 = 1332<br />
(789 + 798 + 879 + 897 + 978 + 987)/6 = 888<br />
(789 + 798 + 879 + 897 + 978 + 987)/8 = 666<br />
(789 + 798 + 879 + 897 + 978 + 987)/9 = 592</p>
<p>&nbsp;</p>
<p><strong>135 + 153 + 315 + 351 + 513 + 531 = 1998</strong></p>
<p>(135 + 153 + 315 + 351 + 513 + 531)/2 = 999<br />
(135 + 153 + 315 + 351 + 513 + 531)/3 = 666<br />
(135 + 153 + 315 + 351 + 513 + 531)/6 = 333<br />
(135 + 153 + 315 + 351 + 513 + 531)/9 = 222</p>
<p><strong>357 + 375 + 537 + 573 + 735 + 753 = 3330</strong></p>
<p>(357 + 375 + 537 + 573 + 735 + 753)/2 = 1665<br />
(357 + 375 + 537 + 573 + 735 + 753)/3 = 1110<br />
(357 + 375 + 537 + 573 + 735 + 753)/5 = 666<br />
(357 + 375 + 537 + 573 + 735 + 753)/6 = 555<br />
(357 + 375 + 537 + 573 + 735 + 753)/9 = 370</p>
<p><strong>579 + 597 + 759 + 795 + 957 + 975  = 4662</strong></p>
<p>(579 + 597 + 759 + 795 + 957 + 975)/2 = 2331<br />
(579 + 597 + 759 + 795 + 957 + 975)/3 = 1554<br />
(579 + 597 + 759 + 795 + 957 + 975)/6 = 777<br />
(579 + 597 + 759 + 795 + 957 + 975)/7 = 666<br />
(579 + 597 + 759 + 795 + 957 + 975)/9 = 518</p>
<p><strong>024 + 042 + 204 + 240 + 402 + 420 = 1332</strong></p>
<p>(024 + 042 + 204 + 240 + 402 + 420)/2 = 666<br />
(024 + 042 + 204 + 240 + 402 + 420)/3 = 444<br />
(024 + 042 + 204 + 240 + 402 + 420)/4 = 333<br />
(024 + 042 + 204 + 240 + 402 + 420)/6 = 222<br />
(024 + 042 + 204 + 240 + 402 + 420)/9 = 148</p>
<p><strong>246 + 264 + 426 + 462 + 624 + 642 = 2664</strong></p>
<p>(246 + 264 + 426 + 462 + 624 + 642)/2 = 1332<br />
(246 + 264 + 426 + 462 + 624 + 642)/3 = 888<br />
(246 + 264 + 426 + 462 + 624 + 642)/4 = 666<br />
(246 + 264 + 426 + 462 + 624 + 642)/6 = 444<br />
(246 + 264 + 426 + 462 + 624 + 642)/8 = 333<br />
(246 + 264 + 426 + 462 + 624 + 642)/9 = 296</p>
<p><strong>468 + 486 + 648 + 684 + 846 + 864 = 3996</strong> </p>
<p>(468 + 486 + 648 + 684 + 846 + 864)/2 = 1998<br />
(468 + 486 + 648 + 684 + 846 + 864)/3 = 1332<br />
(468 + 486 + 648 + 684 + 846 + 864)/4 = 999<br />
(468 + 486 + 648 + 684 + 846 + 864)/6 = 666<br />
(468 + 486 + 648 + 684 + 846 + 864)/9 = 444</p>
<p>&nbsp;<br />
&nbsp;<br />
&nbsp;<br />
&nbsp;<br />
&nbsp;</p>
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